# Find the sum of the terms of A.P 2,6,10,14....,32.

2
by minal61

• Brainly User
2015-01-03T00:48:41+05:30

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A = 2, d = 6 - 2 = 4, n = 32 Sum of n terms = sn = n/2[2a+(n-1)d] Substituting = 32/2[2(2)+(32-1)4] = 16[4+(31)4] = 16[4+124] = 16 * 128 = 2048 Hence Sum of terms of AP 2,6,10,14..........,32. is 2048
• Brainly User
2015-01-03T02:56:48+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Hey the question is wrong as 32 can't be the term as we add 4 consecutively we will get 18,22,26,30,34 see there's no 32
and if you meant that 32 is the number of term than
s=n/2(2a+(n-1)*d)
32/2(4+31*4)
16*(128)
2^4*2^7*(for easier calculation)
=2^11
2048
(*this is answer is only valid when number of term is 32 else the question is wrong)
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