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So the diagonals of the rhombus are at 90°

so the height of the rhombus is 8 cm and base is 15 cm

so using Pythagoras we get the length of 1 side is = 17 cm

so perimeter is 4 x 17 = 68 cm

so the height of the rhombus is 8 cm and base is 15 cm

so using Pythagoras we get the length of 1 side is = 17 cm

so perimeter is 4 x 17 = 68 cm

*The diagonals of the rhombus are perpendicular to each other and bisects each other*

*So the sides of the rhombus is = √{(16/2)² + (30/2)²}*

*= 17 cm*

**cm***Hence perimeter is 17*4 = 68*