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First card can be any thing. second has to be of the same suite.

A gets cards of same suite in draws = 1 * 13/52 = 1/4

outcomes totaling 6 are :  1 + 5, 2+4, 3+3, 4+2, 5+1
    probability =  5 / 36

answer is product of the above two probabilities, as they are independent events.

2 4 2
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When A draws 2 cards with replacement:
  prob. of getting both of same suit=13/52 *13/52=1/16
(because each suit contains 13 cards,trick-when it is 'and' we should multiply their    probabilities,here card-a 'and' card-b)

in 2nd case:
  total outcomes=36
  favourable outcomes=5(5+1,2+4,3+3,1+5,4+2)