# A draws 2 cards with replacement from a pack of 52 cards & B throws a pair of dice what is the chance that A get both the cards of same suit & B get total of 6 ?

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by akritigoel

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by akritigoel

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First card can be any thing. second has to be of the same suite.

A gets cards of same suite in draws = 1 * 13/52 = 1/4

outcomes totaling 6 are : 1 + 5, 2+4, 3+3, 4+2, 5+1

probability = 5 / 36

answer is product of the above two probabilities, as they are independent events.

A gets cards of same suite in draws = 1 * 13/52 = 1/4

outcomes totaling 6 are : 1 + 5, 2+4, 3+3, 4+2, 5+1

probability = 5 / 36

answer is product of the above two probabilities, as they are independent events.

prob. of getting both of same suit=13/52 *13/52=1/16

(because each suit contains 13 cards,trick-when it is 'and' we should multiply their probabilities,here card-a 'and' card-b)

in 2nd case:

total outcomes=36

favourable outcomes=5(5+1,2+4,3+3,1+5,4+2)

prob.=5/36