Three consecutive integers are such that when they are taken in increasing order and multiplied by 2,3 and 4 respectively..they add up to 74.Find the numbers......plzz ans. Fast its urgent!!!!

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Answers

2015-01-05T16:06:46+05:30
Let these Three consecutive numbers are X, Y, and Z.
so Y = X+1, and Z = Y+1 = X+2
A/q,
        2X+3Y+4Z = 74
OR,  2X+3(X+1)+4(X+2) = 74
OR,  2X+3X+4X+3+8 = 74
OR,   9X = 74-11
OR,    X = 63/9 = 7
Therefore numbers are X = 7, Y = 7+1 = 8, and Z = 8+1 = 9

        
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Thnxxxx
your welcome
please answer my question too plzzzz its urgent . u can recognize my question by seeing my profile pic :)
Hey i checked it many times Bt i didnt find
  • Brainly User
2015-01-05T16:09:28+05:30
Let the numbers be x, x+1 and x+2 When multiplied by 2,3and 4= 2x, 3(x+1) and 4(x+2) Thus, 2x+3(x+1)+4(x+2) = 74 2x + 3x+3+ 4x+8 = 74 9x + 11= 74 9x = 74-11 9x = 63 x= 63/9 x= 7 So the numbers are 1. x=7 2. x+1=7+1=8 3. x+2=7+2=9
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