Answers

2014-04-21T19:33:28+05:30
Heat required to convert ice at - 5°c to ice at 0°c = 10*2.1*5 J
heat required to melt ice at 0°c to water at 0°c = 10*3.35*100 J
heat required to convert water at 0°c to water at 100°c = 10*100*4.186 J 
heat required to convert water at 100°c to steam at 100°c = 10*2.256*1000 J
total heat required = (105 + 3350 + 4186 + 22560) J
                           = 30201 J
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