Answers

2015-01-09T15:42:39+05:30
So cos A = 1/sec A

sin A = \frac{\sqrt{sec^2A-1}}{secA}

tan A = \sqrt{sec^2A-1}

cot A = \frac{1}{\sqrt{sec^2A-1}}

cosec A =  \frac{secA}{\sqrt{sec^2A-1}}
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2015-01-09T17:34:26+05:30
All the trigonometric ratios of angle A in the form of sec A 
cos A = 1/sec A.

sin A = √sec²A-1/ secA

tan A = √sec²-1

cot A =1/√sec²-1 

cosec A =  secA/sec²A-1
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