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2015-01-10T10:38:22+05:30
Area of trapezium=1/2 x (sum of parallel sides) x height
1/2 x (16+10) x 6=1/2 x 16 x 6=78 sq.cm
In the case of rhombus the area is 1/2 x diagonal₁ x diagonal₂
But in the figure the second diagonal is not give so we have to find it  out.
We know that the diagonals of a rhombus bisect each other at right angle.
First we have to bisect the diagonal which has length of 16cm into 8 cm.
By using Pythagoras theorem
H²=P²+B²
10²=8²+B²
100=64+B²
100-64=B²
36=B²
6=B
THEREFORE SECOND DIAGONAL=2B=2 X 6=12CM
area of rhombus=1/2*16*12=96cm²
area of trapezium₂=1/2*(10+20)*8
1/2*30*8=120cm²
Area of the figure=(120+96+78)=294cm₂
So the answer is (4) 294cm²
 
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