# A lift of mass 1000kg & its max. accl^n is 1.2m/sec^2 & amax. safe stress is 1.4*10^10n/m^2.find the maximum dimeter of the wire??

1
by sami123

2015-01-10T20:45:40+05:30

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Mass of lift  =1000 kg
maximum acceleration = 1.2 m/s²
when the lift goes upward, the maximum downward force = ma
where a = g+1.2 = 9.8+1.2 = 11 m/s²

maximum tension = 1000×11 = 11000 N
safe stress = 1.4×10¹⁰ N/m²

Stress = Force/area
⇒1.4×10^10 = 11000/A
⇒A = 11000/1.4×10^10 = 7.857×10^-7 m²
⇒ πr² = 7.857×10^-7
⇒ r = √7.857×10^-7/π = 0.0005 m = 0.05cm

diameter = 0.05×2 = 0.1 cm = 1mm
The minimum diameter of the wire should be 1mm. There is no maximum.
Are pressure and stress same? cause u have taken stress →F/A
since pressure is equals to upthrust force per unit area
and stress is equals to restoring force per unit area....
there are different kinds of stresses...and mathematically, pressure and stresses are the same things...
Thanx