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2015-01-15T13:36:27+05:30

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Let us assume a,b,c, d are natural numbers and more than zero.
d = 1 , c = 1 gives b = 2 , a = (10! - 18 ) / 2,   
       a+b+c+d = 18, 14, 391
a = 3, b = 1 c = 1  gives  d = (10! - 14 ) / 7
       a+b+c+d = 5, 18, 403
  
   the value of a+b+c+d lies in between the above two values.

if a,b,c, d can be 0 , then

   values lie  between    10! / 2 and 10! / 7

1 5 1