# An express train travelled at an average speed of 100km/hr stopping for 3 minutes after travelling 75km/hr local train travelling at a speed of 50km/hr stop for 1minute after every 25km. if both the trains start at the same time,how many km did the local time travel in the time in which the express train in which the express train travel in the time in which the express train travelled 600km?

2
by guranshsingh17

2015-01-13T23:58:27+05:30
Express train For travelling 75 km--time--75/100*60=45 min 48 min-----75 km 1 km ------48/75 min 600 km ---48/75*600 min =384 mins Local train travels for 384 mins speed- 50kmph stops for 1 min after 25 one 25kms ----31 mins Nearest multiple of 31 is 372 In 372 mins ----- 372/31*25 kms =300 ins In the remaining (384-372) 12 mins or 1/5 hrs distance traveled=speed *time =1/5*50 =10 km therefore final answer is 310 kms
2015-01-14T00:32:05+05:30

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Express
speed 100 km/hr   stops for  3 min = 1/20 hours after every 75 km.

local train
speed 50 kmph    stops for 1 min after every 25 km
Local train travels 25 km in  25 / 50 = 1/2 hour = 30 min
Include halt, it travels  25 km in 31 minutes.

express
express travels 75 km in :  75/100 = 3/4 hour = 45 min
include halt = 48 min.
express travels  75 km in 48 minutes.
so it travels 600 km in  600 * 48 / 75  = 24 * 16 = 384 minutes

Local
in 384 minutes,  it travels 384 / 31 * 25  km = 390.677  km