Answers

2014-05-14T22:03:45+05:30
No. of mole of 11.2 litre N2 gas at stp is 1/2 mole
no. of mole of NH3 is 34/17 = 2mole
initialy at t = 0          2                                          0          0
                             2NH3  ----------------------------->   N2  +   3H2
at t = 100sec            1                                         1/2       3/2
volume of vessel in litre  250/1000 = 1/4L
change in concentration of NH3 after reaction = 1/(1/4)  =  4
rate = -dx/dt 
      =  - 4/100 
      =   -0.04 
rate is 0.04mole*L^-1*sec^-1              (negative sign simply indicatesthe fall in concentration of NH3)
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