# State the nature of roots of quadratic equation 9x^2=_1

2
by sofiya
^ refers to what
It refers to 9x square
By the way I got the answer
Thank you for seeing my question

2015-01-15T10:50:52+05:30

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9x^2 +1 =0 comparing it with ax^2 +bx +c = 0 we get a= 9 , b= 0 , c = 1 now D = ✔️b^2-4ac = ✔️0-4x9x1 = ✔️-36 => roots are imaginary
When we get a minus sign in the root it shows that roots are imaginary
Mark as best Plz
anyway there is no use of taking root here. simply we can solve here by taking discriminent
Gud thank you
9 x^2 = -1 = i^2 ;; as i = root(-1). x = + 1/3 i or -1/3 i.. imaginary
2015-01-15T11:07:34+05:30

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9x^2 +1 =0 , here a=9, b=0, c=1
then, discriminent
Δ = b² - 4ac
Δ = 0² - 4×9×1
Δ = -36
here the result obtained is less than 0. so, the roots are imaginary.
plz say thanks and mark it as best
easily understandable. nice
9 x^2 = -1 = i^2 ;; as i = root(-1). x = + 1/3 i or -1/3 i.. imaginary number (0,1/3) or (0,-1/3)
It was really helpful
Thank you so much