# 1\x-3-1\x-6=9/20 solve value of x

2
by shanmukhkumar

2015-01-15T11:37:22+05:30

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Take (x-3) (x-6) LCM WE GET (X-6) -(x-3) = 9/20 (x-3)(x-6) => -3 *20 /9 = x^2 -9x + 18 => 3x^2 - 27x + 54 + 20 =0 => 3x^2 -27x +74 =0 now solve the quadratic equation
2015-01-15T18:04:13+05:30

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The maths equation editor is not working properly.  so i write like this,

1/(x-3)  -  1/ (x - 6)  =  9 / 20

-3 / (x^2 -9 x + 18) = 9 /20

x^ - 9 x + 74/3 = 0
as  9^2 - 4*74/3 < 0  so, values of x are imaginary and not real.

x =   [ 9 +- root(17.667) i ] / 2