# Calculate the number of moles of KClO3 that will be required to give 6 moles of oxygen.

2
by Gul705

2015-01-15T19:20:59+05:30

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2KClO ----(On heating with MnO2 [Catalyst])----> 2KCl + 3O

From the above reaction. its clear that
3 moles of O₂ is given out, when 2 moles of KClO₃ decomposes.
6 moles of O₂ is given out, when (x) moles of KClO₃ decomposes.
So,
x = 6 × 2 / 3
= 4 moles.
Therefore, 4 moles of KClO₃ will be required to give 6 moles of Oxygen.

Thanx Angella! I was stuck up with this from the past two days! Can't believe that it was this easy... Anyways thanx sooooo much! :D
Oh! My pleasure! :)
By the way, in the above mentioned reaction, it got typed as KClO₂ instead of KClO₃. I'm sorry, that was accidental!
No problem, i didn't even notice... its really sweet of u!!
:))
2015-01-16T21:05:45+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
3 moles of O₂ is given out, when 2 moles of KClO₃ decomposes.
6 moles of O₂ is given out, when (x) moles of KClO₃ decomposes.
So,
x = 6 × 2 / 3
= 4 moles