# (x-y)^2 + (x+y)^2 = 0 ; Find the value of 'y'.

2
by anjanik

2015-01-16T15:47:25+05:30

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(x-y)² + (x+y)² = 0
x² + y² - 2xy + x² + y² + 2xy = 0
2(x² + y²) = 0
x² + y² = 0
y² = -x²

y =  x sqrt(-1)

y = i x

2015-01-16T17:13:52+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
(x-y)² + (x+y)² = 0
x² + y² - 2xy + x² + y² + 2xy = 0
2(x² + y²) = 0
x² + y² = 0
y² = -x²

as squrt can not be negative therfor no real value of y is possible but it can be imaginery
as negative roots only leds to imaginary parts

ans y=squart root -x^2
as -1=i^2 therfor y=ix
plz mark a s best