# If the length, breath and height of a wall is given L-14feet, B-10feet and H-10feet. what is the area of the wall

2
SURFACE AREA

2(l+b)h=2(14+10)10

480

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SURFACE AREA

2(l+b)h=2(14+10)10

480

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2(LB+BH+LH) AS THE WALL IS A CUBOID

LENGTH=14 FEET

BREADTH=10 FEET

HEIGHT=10 FEET

= 2 X (14 X 10 + 10 X 10 +14 X 10)

=2 X 380

=760

LATERAL SURFACE AREA=

2 X (L + B) X H

=2 X (14 + 10) X 10

=2 X 240

=480

AREA OF WALL =

L X B

=14 X 10

=140

VOLUME OF WALL=

L X B X H

=14 X 10 X 10

=1400

the wall is in shape of cuboid

length=14feet

breath=10feet

height=10feet

surface area= 2(lb+bh+hl)

2 X (14 X 10 + 10 X 10 +14 X 10)

=2 X 380

=760

Lateral surface area=

2 X (L + B) X H

=2 X (14 + 10) X 10

=2 X 240

=480

Area of wall =

L X B

=14 X 10

=140

Volume of wall=

L X B X H

=14 X 10 X 10

=1400