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## Answers

5^x*5^2=7^x/7^2

5^x/7^x=49/25

now

(5/7)^x=49/25

now

if a^x=N

then logto base a(N)=x

so

log base 5/7 (49/25)=x

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5^x*5^2=7^x/7^2

5^x/7^x=49/25

now

(5/7)^x=49/25

now

if a^x=N

then logto base a(N)=x

so

log base 5/7 (49/25)=x