# A cube of edge length 10 cm is placed inside a liquid. the pressure at the upper face of the cube is 1500 pa. find the force exerted by the liquid on this face?

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by kaviyakar

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by kaviyakar

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We know that F =PA

P=1500

A= (0.1)(0.1) =0.01

F=(1500)(0.01)=15N

P=1500

A= (0.1)(0.1) =0.01

F=(1500)(0.01)=15N

Given, P=1500, i.e. P=F/A=1500

now, A=.1*.1=.01

so, F =P*A=1500*.01= 15N

now, A=.1*.1=.01

so, F =P*A=1500*.01= 15N