# The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. Find their present ages (in years).

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Let the ages of the three persons 8 YEARS ago be 4X-8, 7X-8 and 9X-8

ATQ,

4X-8+7X-8+9X-8=56

20X-24=56

20X=56+24

20X=80

X=80/20

X=4

Therefore, present ages are 16,28 and 36