## Answers

**Let AB represent the lighthouse and C & D represent the position of ships Then AB is given equal to 100 m and angle ADB=45 degree and angle ACB= 30 degree**

**tan30 = 1/√3 = AB/AC ⇒AC = AB*√3 = 100√3 m**

**tan45 = 1 = AB/AD ⇒ AD=AB = 100 m**

**Hence distance between two ships,CD = AC+AD = (100√3+100) m**

** =100(√3+1) m**

** =(100*2.73) m = 273 m **