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150 numbers are three digit numbers divisible by 6

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3 digit no divisible by 6 are 102,108,114,.....,996

This forms an AP with ist term,a=102 and common diff,d=6 & last term=996

Let n be the no of terms then

Tn = a+(n-1)d

996 = 102+(n-1)6

894 = (n-1)6

**n= 150**