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2015-01-22T20:52:08+05:30

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Between 23 and 100, first number divisible by 6 = 24 and last number divisible by 6 is 96.

It forms an AP with a=24, d=6
An = 96
⇒ a + (n-1)d = 96
⇒ 24 + (n-1)6 = 96
⇒ (n-1)6 = 96 - 24 = 72
⇒ (n-1) = 72/6 = 12
⇒n = 12+1 = 13

SO there are 13 numbers between 23 and 100 divisible by 6.
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