Answers

2015-01-22T21:15:16+05:30


Let 37a & 37b be the numbers then 37a*37b = 4107 ⇒ab = 3

Co prime with product 3 are (1,3)

Hence, the required numbers are (37*1 , 37*3) i.e (37,1) (37,111)

So the greater no =111

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