# A man has some hens and cows. If the number of heads be 48 and the number of feet equals 140, then the number of hens will be:

1
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all the hen and cows have only one head

then x+y=48 named as equation 1

hen have 2 feet and the cow have 4 feet

then 2x+4y=140 named as equation 2

solve 1 and 2nd equation

2nd equ as 2x+4y=140

1st equ multiply as 2 then 2x+2y=96

subtract 2 equ --------------

2y=44

y=22 (cow = 22)

then x+y=48

x+22=48

then x=24 (hen = 24)