Answers

2015-01-27T00:24:07+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
when 1657 and 2037 are divided with that number, it leaves the remainder 6 and 5

subtract the remainders:
1657 - 6 = 1651
2037-5 = 2032

Now 2032 and 1651 are divisible by that number.
1651 = 13
×127
2032 = 2×2×2×2×127 = 2⁴×127

HCF(1651,2032) = 127

So the greatest number is 127 which on dividing 1657 and 2037 leaves the remainder 6 and 5
0
2015-01-27T12:48:12+05:30
When 1657 and 2037 are divided by HCF would have  remainder 6 and 5
Hence the numbers are (1657 - 6) = 1651 and (2037-5) = 2032
Now  factorizing 2032 and 1651 we have,

           2032 = 2×2×2×2×127 = 2⁴×127

           1651 = 13×127
   HCF = 127
Therefore, the greatest no. is 127 which on dividing 1657 and 2037 leaves the remainder 6 and 5


0