# A purchases 5 chairs and 2 tables for Rs 1625. B purchased 2 chairs and 1 table for Rs 750 . The cost per chair and per table respectively are ....

2
by om2400

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by om2400

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So There are two persons A and B

For B........... 2C

Now for subtracting multiply B by 2 and subtract 2 from 1 we get

cost per chair is 125 Rs and

cost per table is 500 Rs

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Let the cost of one table = Rs. x

the cost of one chair = Rs. y

cost of 5 chairs and 2 tables for Rs 1625

or 5y + 2x = 1625 --------------(1)

cost of 2 chairs and 1 table for Rs 750

or 2y + x = 750 -----------------(2)

(now you have two equations and two variables. You can solve them in any method you want.)

from equation (2), we can write that,

x = 750-2y

putting in equation (1),

5y + 2(750-2y) = 1625

⇒ 5y + 1500 - 4y = 1625

⇒ 5y - 4y = 1625 - 1500

⇒ y =*125 (cost of one chair)*

x =750 - 2y = 750 - 2×125 = 750 - 250 =*500 (cost of one table)*

Hence,**cost per chair is Rs. 125 and cost per table is Rs. 500.**

the cost of one chair = Rs. y

cost of 5 chairs and 2 tables for Rs 1625

or 5y + 2x = 1625 --------------(1)

cost of 2 chairs and 1 table for Rs 750

or 2y + x = 750 -----------------(2)

(now you have two equations and two variables. You can solve them in any method you want.)

from equation (2), we can write that,

x = 750-2y

putting in equation (1),

5y + 2(750-2y) = 1625

⇒ 5y + 1500 - 4y = 1625

⇒ 5y - 4y = 1625 - 1500

⇒ y =

x =750 - 2y = 750 - 2×125 = 750 - 250 =

Hence,