# Best answer and 7 points guaranteed if u find answer.A spring of force constant 800 n/m has extension of 5 cm. find work done in extending from 5 cm to 15 cm

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K = 800 N/m

x₁ = 5 cm = 0.05 m

x₂ = 15 cm = 0.15 m

Energy stored in a spring when it is elongated by a distance x =

x₁ = 5 cm = 0.05 m

x₂ = 15 cm = 0.15 m

Energy stored in a spring when it is elongated by a distance x =