# The sum of the angles of any four-sided figure is 360 degrees. In a quadrilateral, anglea=angle b, angle c is 20 greater than angle a and angle d=40 find the measure of each angle

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by mrambabu1600

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by mrambabu1600

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The Brainliest Answer!

b=x

c=x+20

d=40

sum=360

then x+x+x+20+40=360

3x+60=360

3x=360-60

3x=300

x=300/3

=100

then a=100

b=100

c=120

d=40

sum=360

Now given that angle a = angle b , angle c = 20 + angle a and angle d = 40

Sum of all angles = 360

angle(a+b+c+d) = 360

angle(a + a + 20 + a + 40 ) = 360

3 angle(a) = 300

angle(a) = 100 = angle (b)

angle(c) = 20 + 100 = 120

angle (d) = 40

now we can verify by adding individual angles..........