# A pole 5m high is fixed on the of a tower.the angle of elevation of the top of pole observed from a point A on the ground is 60degree and the angle of depression of the point A from the top of the is 45degree.findthe height of the tower.(take root3=1.732)

2
by airtelbsnl65
something is missing after.." the point A from the top of the .... is 45.."
the point A from the top of the tower is 45

2015-02-01T09:57:16+05:30
Tan 60°=BD/AB
⇒ √3=BD/AB
⇒ AB=BD/√3.....(i)

tan 45°=BC/AB
⇒ 1=BC/AB
⇒  AB=BC.....(ii)

From (i) and (ii)
BD/√3=BC
(BC+5)=√3 BC
5=1.732 BC-BC
5=0.732BC
BC=5/0.732=6.83 m

2015-02-01T10:42:21+05:30

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Let the height of the tower be h

so °

the distance of the point A from the foot of tower be b

so so tan 45 =

⇒ b = x   {tan 45° = 1}

for ΔABC  °

so tan 60° =

⇒ √3x = x + 5

⇒ 0.732x = 5

⇒ x ≈ 6.83 m ANSWER