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For a car moving in a circular track, the necessary centripetal force is provided by the friction.
Let the mass of car = m
maximum velocity for over turn = v
radius of track = 100m
coefficient of friction = 0.2

\frac{mv^2}{r}=\mu mg\\ \\ \frac{v^2}{100}=0.2*9.8\\ \\ v^2=100*0.2*9.8=196\\ \\v= \sqrt{196}=\boxed{14\ m/s}

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