Answers

  • Gun
  • Ambitious
2014-04-16T15:09:00+05:30
2KClO3 ---> 2KCl + 3O2
Therefore, 2 mol of KClO3    gives     3 mol of O2
122.5 g of KClO3     gives     22.4 X 3 L of O2
10 g of KClO3 = 0.081 mol (approx.)
2.24 L of O2 = 0.1 mol
if 3 mol of O2     is obtained from     2 mol of KClO3
0.1 mol of O2     is obtained from     2/3 X 0.1 = 0.06 mol of KClO3
Therefore, amount of pure potassium chlorate in sample = 0.06 mol
% age purity = 0.06 / 0.081 X 100 = 74.07% approx.
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