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A 10g sample of kclo3 gave on complete combustion, 2.24 L of O2 at NTP . what % purity sample of KClO3(potassium chlorates) ?

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Therefore, 2 mol of KClO3 gives 3 mol of O2

122.5 g of KClO3 gives 22.4 X 3 L of O2

10 g of KClO3 = 0.081 mol (approx.)

2.24 L of O2 = 0.1 mol

if 3 mol of O2 is obtained from 2 mol of KClO3

0.1 mol of O2 is obtained from 2/3 X 0.1 = 0.06 mol of KClO3

Therefore, amount of pure potassium chlorate in sample = 0.06 mol

% age purity = 0.06 / 0.081 X 100 = 74.07% approx.