Log in to add a comment

## Answers

conditions for divisible by 4.

conditions for divisible by 4.

**1). Last two digits should be divisible by 4.**

2). or last two digit be 0, 0.

so we can take these two digits from 0, 2 and 4

2). or last two digit be 0, 0.

case.(1)

no. of 4 digit's number divisible by 4,if their last digit(unit place) be 0.

option for put the number at tens place = 3 : (0, 2 & 4)......{If repetition is allowed}

option for 100s place = 6 : (0, 1, 2, 3, 4, 5)

option for 100s place = 5 : (1, 2, 3, 4, 5)

no. of 4 digit's numbers divisible by for, their last digit be Zero. = 3 × 6 × 5 = 90

case.(2)

no. of 4 digit's numbers divisible by 4, if last digit be 2 .

option for put the digit at tens place = 3 : (1,3 & 5)

options for hundreds place = 6 :(0, 1, 2, 3, 4 & 5)

options for 1000s place = 5 : (1, 2, 3, 4 & 5)

No. of 4 digit's numbers divisible by 4, their last digit be 2. = 3 × 6 × 5 = 90

case.(3)

no. of 4 digit's numbers divisible by 4, if last digit be 4.

option for tens place = 3 : (0, 2 & 4)

options for 100s place = 6 : (0, 1, 2, 3, 4 & 5)

options for 1000s place = 5 : (1, 2, 3, 4 & 5)

no of 4 digit's numbers divisible by 4, their last digit be 4. = 3 × 6 ×5 = 90

From case (1), (2 ) and (3)----

**Total no. of 4 digit's numbers , divisible by 4 formed by digits 0, 1, 2, 3, 4 &5 .=****90 + 90 + 90 = 270**

NOTE;

__Here repetition is allowed. take in care .__