# The area of a rectangle is 192 sq cm and its perimeter is 56 cm . Find the dimensions of the rectangle .

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The Brainliest Answer!

= l = 192/b

The perimeter = 2l + 2b = 56

= 2*(192/b) + 2b = 56

= (384/b) +2(b^2) =384

rearranging&dividing by 2 = b^2 - 28b + 192 =0

= b^2 - 16b - 12b + 192 = 0

= b(b - 16) - 12(b - 16) = 0

= (b - 16) (b -12) =0

so b-16=0 i.e b= 16

or

b-12 = 0 i.e b = 12

if l = 12 then b = 16 or vice versa

area = l * b = 12 * 16 = 192

peri = (2 *12)+(2 * 16) = 24 +52 = 56

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