Answers

2015-02-04T23:11:47+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Case 1:
numbers with 3 are like 3,13,23,......,303
they are in AP with a=3, d=10
let the total number of pages with the digit 3 be n.
303 = 3 + (n-1)10
⇒ n-1 = 300/10 = 30
⇒ n = 31
number of pages = 31

case 2:
number like 30,31,...39; 130,131,...139; 230,231,...239
from 30 to 39 - there are 10 numbers 
from 130 to 139 - there are 10 numbers
from 230 to 239 - there are 10 numbers
total = 10+10+10 = 30

but we have already counted 33,133 and 233.
so number of pages = 30-3 = 27

case 3:
the number 300,301 and 302. (303 has already been counted)
so numbers = 3

So total number of pages = 31+27+3 = 61

every number having three has only one three except 33,133,233 and 303.
number of pages with 2 threes = 4
number of pages with only one three = 61 - 4 = 57

total number of printing of 3 = 57×1 +4×2 = 57+8 = 65.

So the digit 3 has been printed 65 times and number of pages with only one 3 present is 57.
2 2 2