# LCM of two quantities is xy times of their HCF. if one of them is x2-xy and hcf is x-y then find the other quantities

2
by sanaparveen161

## Answers

2015-02-06T16:14:26+05:30

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HCF = (x-y)
LCM of two quantities is xy times of their HCF
so LCM = xy(x-y)

one number = x²-xy = x(x-y)
let the other number be a.

since product of numbers is equal to product of their LCM and HCF

So other number is y(x-y)
2015-02-07T01:16:38+05:30

### This Is a Certified Answer

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Product of two nos=HCF X LCM
x²-xyX 2nd no= (x-y)Xxy(x-y)
⇒2nd no=(x-y)(x-y)xy/x(x-y)
⇒2nd no=xy-y²