# In attachment BD is one of the diagonal of quadrilateral. ABCD . if AL prependicular BD and CM prependicular on BD , Show that , Area of quad.ABCD = 1/2 * BD * ( AL + CM ) ..

2
by ananth0

2015-02-07T13:14:56+05:30

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given , AL is height of TriangleABD , CM is the height of triangleDBC , BD is the common base of both the triangleABD & TriangleDBC  .
to prove - 1/2*BD* AL + CM

proof -  in triangle ABD ,
area =
---------(eqn .i)
in triangle DBC,
area =
=    ------------- ( eqn. ii )

on adding eqn. i & ii , we get ,
area of quad. ABCD = ar.( traingle ABD + triangle DBC )
=
=
=

2015-02-07T13:31:09+05:30

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The area of figure ABCD = ar(ΔABD)+ar(ΔCBD)
=⇒⇒⇒