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2015-02-07T15:54:22+05:30

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Inner radius, r_i=10\ m
width = 2m
outer radius, r_o=10+2=12\ m

Area of path =  \pi r_0^2- \pi r_i^2= \pi (r_o^2-r_i^2)= \pi (12^2-10^2)=3.142*44=138.25\ m^2

rate of gravelling = Rs. 100 per m²
total cost = 138.25×100 = Rs. 13825
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2015-02-07T16:41:56+05:30

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Inner radius=10m
outer  radius= 12m
Area of graveling=area of outer circle-area of inner circle=(144-100)π
=44π
rate of graveling of 1 m²=100 Rs
rate of gravelling of 44πm²=100×44×22/7=13816Rs
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