Answers

2014-04-15T11:48:29+05:30
-x^2+x+12<=0
or, x^2-x-12>=0
or,(x+3)(x-4)>=0
thus, either x=-3 or x=4
or x>4 or x<-3
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  • Brainly User
2014-04-15T11:54:19+05:30
-x²+x+12≤0
=x²-x-12≥0
=(x+3)(x-4)≥0
=x=-3 or x=4
=x is greater than 4 or x is smaller than 3
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