For an A.P.T6=47 and T10=10 then find T30.

2
by gite

2015-02-07T19:57:54+05:30

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So let a be first term and d be common difference

we have t6 = a + 5d = 47 ..... i

and t10 = a + 9d = 10 .......... ii

subtracting i from ii

- 4d = 37

d = - 37/4

so a = 93.25

so t30 = a + 29d = - 175 ANSWER

2015-02-07T20:10:15+05:30

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
The general form of AP = a, a+d, a+2d.....

Tn=a+(n-1)d

T6 = a+5d = 47.......(1)

T10 = a+9d = 10........(2)

Subtracting both,

-4d = 37

d = -

Substituting d value in (1)

a + 5  = 47

a =

a=93.25

T30 = 93.25 + (30-1)

T30 = 93.25 - 268.25

T30 = - 175

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