# Solve the linear equations x-2y=8 and 5x+3y=1 by algebraic method

2
by syed52

2015-02-11T20:46:28+05:30

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x-2y=8 is given
multiply it with 5
then it will be 5x-10y=40 --------------- 1
and 2nd equation is 5x+3y=1 ----------------2
by 1 and 2 we get
5x - 10y = 40
(-)5x + 3y=    1
-------------------------
13y = 39
---------------------------
then y=39/13 = 3
y = 3
by substituting it in 2
5x+3(3)=1
5x=1-9
5x=8
x=8/5

2015-02-11T21:04:23+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
x-2y=8 is given
multiply it with 5
then it will be 5x-10y=40..........(i)
and 2nd equation is 5x+3y=1.........(ii)
by equation (i)and(ii) we get
3x-10y=40
(-)5x+3y=1
...................................
13y=39
then y=39/13=3
y=3
by subsiting it in 2
5x+3(3)=1
5x=1-9
5x=8
x=8/5