# The parallel sides of a trapezium are in the ratio 3 : 4 and the perpendicular distance between them is 12 cm. if the area of the trapezium is 630 cmsquare, then its shorter of the parallel sides is??

2
by dharshuvandu

2015-02-11T21:48:53+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
parallel sides of trapezium =  3 : 4
height =  12 cm
area =  630 cm^2
let parallel sides of trapezium =  3x and 4x

area of trapezium =
630 cm^2 =
x  =  630 / 42
=  15
parallel sides are =  4 * 15 =  60 cm
3 * 15  = 45 cm

2015-02-11T21:56:40+05:30

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
So formula for area of trapezium(A) =   x sum of parallel sides(S) x perpendicular distance between parallel sides (P)

so here S = 4x + 3x cm = 7x cm

A = 630 cm²

P =  12 cm

so 630 =   x 7x x 12

⇒  x =

⇒  3x = 45 cm ANSWER
i need the complete steps...plzzzzzzzzzzzz
so using the same formula we get 180 = 1/2 x (2x + 6) x 9
u say how u said for the before answer
x + 3 = 20 i.e. x = 17 cm so the larger side is x + 6 = 17 + 6 = 23 cm
i did nt understand