Answers

2015-02-13T18:37:35+05:30
We get this by Pythagoras' theorem, e.g. AB² = (3 -(-2))² + (2 -(-3))² 

so AB² = 50. Similarly, AC² = 1² + 1² = 2², so right away we see that the triangle isn't equilateral. Meanwhile BC² = (-2 -2)² + (-3 -3)² = 16 + 36 = 52 - sightly more than AB². So it's not isosceles either. 

Finally, we should check to see if it's right-angled. 

The vector AB is (-5, -5); AC is (-1, 1); and BC = (4, 6). 

Notice that AB and AC are indeed perpendicular, meaning that the triangle has a right angle at A.
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2015-02-14T10:40:01+05:30
A=(3,2)
b=(-2,-3)
c=(2,3)
distance²=(x2-x1)²+(y2-y1)²
ab²=(3--2)²+(2--3)²
   = 25+25
ab=√50
ac²=(3-2)²+(2-3)²
     =1+1
ac=√2
bc²=(2--2)²+(3--3)²
     = 16+36
bc= √52
if this triangle is a right angled triangle..
bc²=ab²+ac²(pythagorus
52=50+2

so it is a right angled triangle

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