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2015-02-14T16:23:26+05:30

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given ,( time taken per day ) t = 10 hrs.
         ( power )   P = 500 w
        ( energy )   E = ?   
   P =  \frac{E}{t} 

    P * T = E
    500 * 10 = 5000 w    
 energy use in 1day  = 5000 * 3600 * 10 =  18000 kj 
 energy used in month of april ( 30 days ) = 18000 * 30 = 540000 kj 

  


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2015-02-18T22:24:34+05:30

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Power = 500W
so energy consumed is 500J per second.
energy consumed in 1 hour = 500×3600 = 1800000J = 1800 kJ
It is used for 10 hours a day. 
So energy consumed in a day = 1800kJ×10 = 18,000 kJ
energy consumed in 1 month(30days) = 30×18,000 kJ = 5,40,000 kJ=5.4×10⁵ kJ

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