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100 can be written as 10² and (100-100) can be written as 10(10-10)
then, 100-100/100-100 can be written as
           by a²-b² = (a+b)(a-b)
          = (10+10)(10-10)/10(10-10)
          = (10+10)/10
          = 20/10
          = 2
hence it is proved
3 5 3
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