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quadratic polynomial means having degree 2

yeah

wt does ^ means

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Comment has been deleted

quadratic polynomial means having degree 2

yeah

wt does ^ means

power

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Given polynomial equation : -x⁴ + 80 x + 36 = 0

Let us express an equation of degree 4 as

P(x) = (x - a)(x-b)(x - c) ( x- d) = 0

Thus either all are real roots, or two of them are real or none of the roots are real. the reason is that we know that imaginary roots appear in pairs.

expand P(x) = [ x² - (a+b) x + ab ] [ x² - (c+d) x + cd ] = 0

x⁴ - [a+b+c+d] x³ + x² [ ab+cd+ac+ad+bc+bd] - [abc+abd+acd+bcd] x +abcd=0

*Sum of roots a+b+c+d = 0 as in the given equation the coefficient of x³ term is 0.*

==========================================

if the given equation is a* quadratic equation *: perhaps there is a small typing mistake in that. then

Q(x) = -x² + 80 x + 36 = 0

let P(x) = x² - 80 x - 36 = 0

Using the change of sign of the coefficients in P(x) we know that there is one positive real root and one negative real root.

*the sum is the minus of coefficient of the x term. 80.*

quadratic equation is expressed as (x - a)(x - b) = x² - (a+b)x+ab = 0

Let us express an equation of degree 4 as

P(x) = (x - a)(x-b)(x - c) ( x- d) = 0

Thus either all are real roots, or two of them are real or none of the roots are real. the reason is that we know that imaginary roots appear in pairs.

expand P(x) = [ x² - (a+b) x + ab ] [ x² - (c+d) x + cd ] = 0

x⁴ - [a+b+c+d] x³ + x² [ ab+cd+ac+ad+bc+bd] - [abc+abd+acd+bcd] x +abcd=0

==========================================

if the given equation is a

Q(x) = -x² + 80 x + 36 = 0

let P(x) = x² - 80 x - 36 = 0

Using the change of sign of the coefficients in P(x) we know that there is one positive real root and one negative real root.

quadratic equation is expressed as (x - a)(x - b) = x² - (a+b)x+ab = 0