# An object of mass 10kg is dropped from a height of 100 cm. find: a) its kinetic energy b)velocity just as it reaches the ground (g=10m/s2)

2
by kanwaljeetnancy

2015-02-16T15:22:51+05:30

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mass of the object ( m ) = 10 kg
height (h) = 100cm = 1m
g = 10m/s
K.E.=

when the body reaches the ground its P.E. changes into K.E.
object on the top = K.E.on the ground
mgh = K.E.on the ground
gh=
v =
v =
v =   m/s

P.E = mgh
= 10 * 10 * 1
= 20 j

KE is 100J.
sory KE is 100 j
2015-02-17T13:21:50+05:30

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Final velocity of the body when it reaches the ground (100 cm =1 m)

v^2 = u^2 - 2as = 0 - {2*(-10)*1} = 20

So velocity just as it reaches the ground = (Square root of 20) m/s

Kinetic energy = 1/2*m*v^2 = 1/2*10*20 = 100 J