Answers

2015-02-17T21:55:37+05:30
Ad is the median
so, bd=dc
consider tri.BCF
d is the m.p of side bc
draw a line DG from D parallel to BF
according to M.P.theorem, CG=FG..................(1)
now,consider tri.ADG
e and f are m.p's of sides AD and AG respectively
therefore AF=FG.............................................(2)
from 1 and 2 we get
AF=FG=CG
i.e,AF is 1/3 of the side AC
HENCE THE PROOF

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