Answers

2015-02-17T17:16:30+05:30
In quad. abcd
 t is mid-pt. of ad
if there is mid-pt. s  on cb 
ar. of abst =ar. of stdc
therefore ar. of cst=45/3=15cm sq.
therefore ar. sdc=15cm sq.
sc is median in triangle adc
ar. of adc=15*2=30 cm sq.
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