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LHS=tan(2*Cot^{-1}\sqrt{\frac{1-Cos\ x}{1+Cos\ x}})+Tan\ x\\\\1-Cos\ x=2\ Sin^2(\frac{x}{2})\\\\1+Cos\ x=2\ Cos^2(\frac{x}{2})\\\\LHS=Tan(2*Cot^{-1}\sqrt{Tan^2(\frac{x}{2})})+Tan\ x\\\\We\ know\ Tan\frac{x}{2}= Cot(\frac{\pi}{2}-\frac{x}{2})\\\\LHS=Tan(2*(\frac{\pi-x}{2}))+Tan\ x\\\\=Tan(\pi-x)+Tan\ x=-Tan\ x + Tan\ x = 0
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sir its tan theta instead of tanx at the last plz can u edit it sir plz tomorrow m hving my board exam 2015 ISC