Answers

2015-02-21T12:43:41+05:30
(ii) IBr2 :- :- No of valence electrons in IBr2- is 7+(2*7) +1 = 22 The noble gas compound having 22 electrons is XeF2 = 8+ (2*7) = 22 IBr2- is linear and so is XeF2
  
0
Please be my friend mark as brainliest and please say thanks
2015-02-23T11:37:52+05:30
XeF2 is isostructural with IBr2-
0